document.write( "Question 1165370: A person's website specializes in the sale of rare or unusual vegetable seeds. He sells packets of sweet-pepper seeds for $2.32 each and packets of hot-pepper seeds for $4.56 each. He also offers a 16-packet mixed pepper assortment combining packets of both types of seeds at $2.88 per packet. How many packets of each type of seed are in the assortment? \n" ); document.write( "
Algebra.Com's Answer #789859 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "If a formal algebraic solution is not required, here is a quick and easy way to solve any 2-part mixture problem like this. \n" ); document.write( "(1) Find where the per-packet price for the mixture lies between the per-packet prices of the two types of seeds. \n" ); document.write( "4.56-2.32 = 2.24 \n" ); document.write( "2.88-2.32 = 0.56 \n" ); document.write( "0.56/2.24 = 1/4 \n" ); document.write( "The per-packet price for the mixture is one-fourth of the way from $2.24 to $4.56. \n" ); document.write( "(2) That means 1/4 of the packets in the assortment are packets of the higher-priced seed. \n" ); document.write( "ANSWER: 1/4 of 16 packets, or 4 packets, of the hot-pepper seeds; the other 12 packets are of sweet-pepper seeds. \n" ); document.write( "CHECK: \n" ); document.write( "12(2.32)+4(4.56) = 27.84+18.24 = 46.08 \n" ); document.write( "16(2.88) = 46.08 \n" ); document.write( " \n" ); document.write( " |