document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=108327>Question 108327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of a 90% gasloine mix and a 75% gasoline mix are needed for 1200L of an 85% gasoline mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78981 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78981\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .9x+.75(1200-x)=.85*1200<BR>\n" );
document.write( ".9x+900-.75x=1020<BR>\n" );
document.write( ".15x=1020-900<BR>\n" );
document.write( ".15x=120<BR>\n" );
document.write( "x=120/.15<BR>\n" );
document.write( "x=800 is the amount of 90% gas.<BR>\n" );
document.write( "1200-800=400 of 75% gas.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( ".9*800+.75*400=.85*1200<BR>\n" );
document.write( "720+300=1020<BR>\n" );
document.write( "1020=1020 <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );