document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1165296>Question 1165296</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A theater can accommodate at most 450 movie goers per show. The manager uses the formula C = 2(h + 150,000/ h) to determine the cost of operating the theater with people. How many people must watch a show to keep the cost down to Php1,600? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #789773 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=789773\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1600=2(h+150000/h)<BR>\n" );
document.write( "800=h+150000/h<BR>\n" );
document.write( "multiply through by h<BR>\n" );
document.write( "800h=h^2+150000<BR>\n" );
document.write( "so 0=h^2-800h+150000<BR>\n" );
document.write( "0-(h-500)(h-300)<BR>\n" );
document.write( "h=300 or 500, but the theater can only hold 450, so h=300 is the answer.<BR>\n" );
document.write( "the cost will be 1600 Php\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );