document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1165291>Question 1165291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an arc of a circle of radius 7cm subtend on angle of 120 degree at the centre, find its perimeter </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #789756 by </B><A HREF=/tutors/aboutme.mpl?userid=Seutip><B>Seutip(231)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Seutip><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Seutip><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=789756\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r = 7cm<BR>\n" );
document.write( "ϴ=120°=(120°)(2π/360)=2π/3<BR>\n" );
document.write( "Do you mean the length of the arc as the perimeter?<BR>\n" );
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document.write( "s (length of the arc) = ϴ*r\r<BR>\n" );
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document.write( "s=rϴ<BR>\n" );
document.write( "s=(7) (2π/3) <BR>\n" );
document.write( "s=14π/3=14.66cm\r<BR>\n" );
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document.write( "Hope that helps!  </SPAN>\n" );
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