document.write( "Question 1165286: The probability of being a smoker among a group of cases with lung cancer is
\n" ); document.write( "0.75. Calculate the probability that in a group of 6 cases, you have at least 3
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Algebra.Com's Answer #789754 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "One less calculation to compute this as 1-Pr(2 or fewer smokers)
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\n" ); document.write( "\n" ); document.write( "Probability of nonsmoker is 1-0.75 = 0.25
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\n" ); document.write( "\n" ); document.write( "Probability of at least 3 smokers = 1 - (probability of 2 or fewer smokers)
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\n" ); document.write( "\n" ); document.write( "Probability of 0 smokers: \"+0.25%5E6+=+0.0002441+\"
\n" ); document.write( "Probability of 1 smoker : \"+0.25%5E5+%2A+0.75%5E1+%2A+6C1+=+0.0043945+\"
\n" ); document.write( "Probability of 2 smokers: \"+0.25%5E4+%2A+0.75%5E2+%2A+6C2+=+0.0329590+\"
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\n" ); document.write( "Sum is 0.037598
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\n" ); document.write( "\n" ); document.write( "Proability of at least 3 smokers = 1-0.037598 = \"+highlight%28+0.96240+%29+\"
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\n" ); document.write( "\n" ); document.write( "You can try solving it in a direct method (pr(3)+pr(4)+pr(5)+pr(6) smokers) to prove to yourself that the answer comes out the same.

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