document.write( "Question 108168: 
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document.write( "can someone help me solve: given logb3 = 0.6826 \r\n" );
document.write( "and logb7 = 1.2091, evaluate logb21. \r\n" );
document.write( "completely lost.
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Algebra.Com's Answer #78966 by Edwin McCravy(20059)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "can someone help me solve: given logb3 = 0.6826 \r\n" );
document.write( "and logb7 = 1.2091, evaluate logb21. \r\n" );
document.write( "completely lost.\r\n" );
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document.write( "You need to know this basic rule of logarithms:\r\n" );
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document.write( "logb(X·Y) = logbX + logbY\r\n" );
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document.write( "and the fact that 21 = 3·7, to get\r\n" );
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document.write( "logb(3·7) = logb3 + logb7\r\n" );
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document.write( "then since you are given that \r\n" );
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document.write( "logb3 = 0.6826 and logb7 = 1.2091\r\n" );
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document.write( "logb(3·7) = logb3 + logb7 = 0.6826 + 1.2091 = 1.8917\r\n" );
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document.write( "Edwin
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