document.write( "Question 1165175: a total of $4300 was invested, part of it at 8% and the remainder at 13%. if the total yearly interest amounted to $375. how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #789636 by josgarithmetic(39620)\"\" \"About 
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If y invested at 13% then 4300-y invested at 8%\r
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\n" ); document.write( "\n" ); document.write( "\"0.13y%2B0.08%284300-y%29=375\"
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