document.write( "Question 1165105: in planning her retirement Liza deposit some money at 3.5% interest with twice as much deposited at 5% find the amount deposited at each rate if the total annual interest income is $1755 she deposited blank at 3.5% in blank at 5% \n" ); document.write( "

Algebra.Com's Answer #789564 by greenestamps(13206) $\"\"$ $\"About$

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\n" ); document.write( "The other tutor misread the problem, having twice as much at 3.5% as at 5%, instead of the other way around.

\n" ); document.write( "You can solve the problem by his method -- just make x the amount invested at 3.5% and 2x the amount invested at 5%.

\n" ); document.write( "Here is another way to solve the problem.

\n" ); document.write( "With twice as much invested at 5% as at 3.5%, the average rate of return is

\n" ); document.write( " $\"%282%28.05%29%2B1%28.035%29%29%2F3+=+.045\"$

\n" ); document.write( "Then, since the total interest was $1755,

\n" ); document.write( " $\"1755+=+.045x\"$
\n" ); document.write( " $\"x+=+39000\"$

\n" ); document.write( "The total amount invested was $39,000. With twice as much at 5% as at 3.5%, that means $13,000 at 3.5% and $26,000 at 5%.

\n" ); document.write( "ANSWER: $13,000 at 3.5%; $26,000 at 5%.

\n" ); document.write( "CHECK: .035(13000)+.05(26000) = 455+1300 = 1755

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