document.write( "Question 1165055: a coin collection consists of 12 coins with a total value of $1.20. if the collection consists only of nickels, dimes, and quarters and the number of dimes is two more than twice the number of nickels, how many of each type of coin are in the collection? \n" ); document.write( "

Algebra.Com's Answer #789509 by ikleyn(52776) $\"\"$ $\"About$

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document.write( "Let the number of nickels be x; then the number of dimes is (2x+2)\r\n" );
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document.write( "and the number of quarters is the rest coins, i.e. (12-x - (2x+2)) = 10-3x.\r\n" );
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document.write( "Next, I write the total money equation\r\n" );
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document.write( "    5x + 10*(2x+2) + 25*(10-3x) = 120  cents.\r\n" );
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document.write( "Simplify \r\n" );
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document.write( "    5x + 20x + 20 + 250 - 75x = 120\r\n" );
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document.write( "    -50x = - 150\r\n" );
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document.write( "     x   = 3.\r\n" );
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document.write( "ANSWER.  3 nickels,  2*3+2 = 8 dimes and the rest coins, i.e. 12 - 3 - 8 = 1, is/(are) quarters.\r\n" );
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