document.write( "Question 108309: The perimeter of a rectangle is to be no greater than 300 in.,
\n" ); document.write( "and the length must be 125 in.
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Algebra.Com's Answer #78945 by HyperBrain(694)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "perimeter=2*(length+width)\r
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\n" ); document.write( "\n" ); document.write( "Let x=length
\n" ); document.write( "____y=width
\n" ); document.write( "____2(x+y)=perimeter\r
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\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is to be no greater than 300 in., \r
\n" ); document.write( "\n" ); document.write( "\"2%28x%2By%29%3C=+300\"\r
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\n" ); document.write( "\n" ); document.write( "But, \"x=125\" (the length must be 125 in).So,\r
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\n" ); document.write( "\n" ); document.write( "\"2%28y%2B125%29%3C=300\"
\n" ); document.write( "\"2%28y%2B125%29%2F2%3C=300%2F2\"
\n" ); document.write( "\"y%2B125%3C=150\"
\n" ); document.write( "\"y%3C=25\"\r
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\n" ); document.write( "\n" ); document.write( "Thus, the maximum measure of the width is 25 inches\r
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\n" ); document.write( "\n" ); document.write( "Power up,
\n" ); document.write( "HyperBrain!
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