document.write( "Question 1164923: Given a parallelogram ABCD, side AB is extended to a point P such that
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document.write( "AB : BP = 2 : 1 and side CD is extended to a point Q such that D is the
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document.write( "midpoint of CQ. The line PQ meets the diagonal AC at Z and the sides
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document.write( "BC and AD at X and Y , respectively.
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document.write( "(a) Find the ratio of the areas of triangles AZY and CZX.
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document.write( "(b) Find the ratio of the lengths PX and ZY.
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document.write( "I am confused with this. Do you know how to do it \n" );
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Algebra.Com's Answer #789421 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll give you a hint. Angle AZP is congruent to Angle CZQ by vertical angles. Angle DAC is congruent to angle BCA by opposite interior angles of a transversal and angles BAD and BCD are congruent for the same reason, but since angle BAD is the sum of angle BAC and CAD, and angle BCD is the sum of BCA and ACD, angles ACD and BAC are congruent. And APZ is congruent to CQZ by opposite interior angles. Therefore triangles APZ and CQZ are similar by AAA. Using a similar argument, triangles AZY and CZX are similar by AAA. Then AP:CQ is 3:4. You can take it from there.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |