document.write( "Question 1164927: The diagonals of a parallelogram meet at K. If AK= 3x+1, KC= x+5, BK= 2x+3, and KD= 4x-1, what kind of parallelogram is ABCD. Why?
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Algebra.Com's Answer #789414 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Set the expressions for AK and KC equal to each other because you know that the diagonals of a parallelogram bisect each other. Solve for , then substitute that value in each of the four expressions. Compare the measures of AC and BD. What can you conclude?\r
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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