document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1164975>Question 1164975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the multiples of 3 and 7 are removed from the series 1+2+3...+150. the resulting sum is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #789413 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=789413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "Add all the numbers from 1 to 150.  From that subtract the sum of all the numbers from 1 to 150 that are divisible by 3.  Then subtract the sum of all the numbers from 1 to 147 (the last number before 150 that is divisible by 7) that are divisible by 7.  Then calculate the sum of the numbers from 1 to 147 that are divisible by 21 and add them back because you have subtracted them twice -- once when you did the 3s and once when you did the 7s.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \sum_{i=1}^{150}\,i\ -\ \sum_{i=1}^{50}\,3i\ -\ \sum_{i=1}^{21}\,7i\ +\ \sum_{i=1}^{7}\,21i\">\r<BR>\n" );
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document.write( "You can do your own arithmetic.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \ \\r\"> </SPAN>\n" );
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