document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1164926>Question 1164926</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In ABCD, ∠B= (2x+y)°, ∠D= (x+2y-5)°. If ∠A= 100°, what values of x and y will make ABCD a parallelogram?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #789403 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=789403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a parallelogram, the opposite angles are equal.  If angle A = 100, then angle C = 100<BR>\n" );
document.write( "The other two angles must sum to 360 - 100 - 100 = 160.<BR>\n" );
document.write( "Thus each angle is 80:<BR>\n" );
document.write( "x + 2y - 5 = 80<BR>\n" );
document.write( "2x + y = 80 -> y = 80 - 2x<BR>\n" );
document.write( "x + 2(80 - 2x) - 5 = 80<BR>\n" );
document.write( "3x = 75 -> x = 25<BR>\n" );
document.write( "Thus y = 80 - 50 = 30<BR>\n" );
document.write( "x = 25, y = 30<BR>\n" );
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