document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1164915>Question 1164915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use two equations in two variables to solve the application. See Example 4. (Objective 1)\r<BR>\n" );
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document.write( "Peter invested some money at 6% annual interest, and Martha invested some at 12%. If their combined investment was $6,000 and their combined interest was $510, how much money did Martha invest?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #789383 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=789383\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=6000. x is  at 6%, y is at 12%<BR>\n" );
document.write( ".06x+.12y=510<BR>\n" );
document.write( "6x+12y=51000<BR>\n" );
document.write( "-6x-6y=-36000, multiplying the top by -6<BR>\n" );
document.write( "6y=15000<BR>\n" );
document.write( "y=$2500 @ 12% =$300<BR>\n" );
document.write( "x=$3500 @ 6%=$210 </SPAN>\n" );
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