document.write( "Question 1164930: ABCD is a rectangle. If the diagonals intersect at N and ∠ANB = 104°, find ∠BDA and ∠BAC.
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Algebra.Com's Answer #789381 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Triangle ANB is isosceles because the two diagonals are congruent and bisect each other. Hence angle ABD is congruent to angle BAC. Since the sum of the angles in a triangle is 180, to find the measure of either angle ABD or angle BAC, subtract the measure of angle ANB from 180 and divide by 2.\r
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\n" ); document.write( "\n" ); document.write( "Adjacent angles formed by two intersecting lines are supplementary, so you can easily calculate the measure of angle AND and from that, using the same logic as above, you can find the measure of angle BDA.\r
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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