document.write( "Question 1164940: The gasoline tank of a car contains 50 liters of gasoline and alcohol, the alcohol comprising 25%. How much of the mixture must be drawn off and replaced by alcohol so that the tank contain a mixture of which 50% is alcohol? \n" ); document.write( "
Algebra.Com's Answer #789372 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! G+A=50 l \n" ); document.write( "A=12.5 l \n" ); document.write( "G=37.5 l \n" ); document.write( "remove x liters and replace with x alcohol \n" ); document.write( "each liter that is removed is 0.75 G and 0.25 A\r \n" ); document.write( "\n" ); document.write( "37.5-0.75x=12.5-0.25x+x=12.5+0.75x \n" ); document.write( "25=1.5x \n" ); document.write( "x=16 2/3 l drawn off\r \n" ); document.write( "\n" ); document.write( "after drawing off, there is 33 1/3 liters in tank and 1/4 is alcohol or 8.33 liters. \n" ); document.write( "and 16 2/3 liters alcohol to the tank and have 50 liters again and 25 liters of alcohol or 50%\r \n" ); document.write( "\n" ); document.write( "it is 16 2/3 liters.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |