document.write( "Question 1164943: A stone is thrown horizontally at a speed of +5.0m/s off the top of a cliff 78.4m high. \r
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\n" ); document.write( "b) how far from the base of the cliff does the stone strike the ground? answer 20 m
\n" ); document.write( "c) what are the horizontal and vertical componennts of the velocity of the stone before it hits the ground (vyf=-39.2m/s, vx= 5m/s)
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Algebra.Com's Answer #789369 by ikleyn(52797)\"\" \"About 
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\n" ); document.write( "A stone is thrown horizontally at a speed of +5.0m/s off the top of a cliff 78.4m high.
\n" ); document.write( "a) how long does it take the stone to reach the bottom of the cliff? (answer 4 sec)
\n" ); document.write( "b) how far from the base of the cliff does the stone strike the ground? answer 20 m
\n" ); document.write( "c) what are the horizontal and vertical componennts of the velocity of the stone before it hits the ground (vyf=-39.2m/s, vx= 5m/s)
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\n" ); document.write( "\n" ); document.write( "            From my school years,  I remember the standard mantra solving this classic  Physics problem.\r
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document.write( "The thrown body participates in two movements.\r\n" );
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document.write( "One movement is horizontal with the horizontal velocity  v = 5.0 m/s = constant.\r\n" );
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document.write( "The other movement is vertical uniformly accelerated with the vertical acceleration of g = 9.81 m/s6^2.\r\n" );
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document.write( "The time to get the bottom of the cliff is determined from the equation\r\n" );
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document.write( "    \"%28g%2At%5E2%29%2F2\" = H,   or  \"%289.81%2At%5E2%29%2F2\" = 78.4 m,\r\n" );
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document.write( "which gives\r\n" );
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document.write( "    \"t%5E2\" = \"%282%2AH%29%2Fg\" = \"%282%2A78.4%29%2F9.81\" = 15.984;  t = \"sqrt%2815.984%29\" = 4 seconds (approximately).\r\n" );
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document.write( "During this time, the horizontal distance is  d = v*t = 5.0 * 4 = 20 m, approximately.\r\n" );
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document.write( "Horizontal component of the final velocity is v = 5.0 m (the given constant).\r\n" );
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document.write( "Vertical component of the final velocity is  \"v%5Bvert%5D\" = -g*t = -9.81*4 = -39.2 m/s.\r\n" );
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