document.write( "Question 1164936: x takes 3 hrs more than y to walk 30 km. but if x doubles his pace he is ahead of y by 1 1/2 hours.find their speed of walking \n" ); document.write( "

Algebra.Com's Answer #789361 by josgarithmetic(39617) $\"\"$ $\"About$

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document.write( "               SPEED        TIME        DISTANCE\r\n" );
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document.write( "x             30/(t+3)      t+3          30\r\n" );
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document.write( "y             30/t          t            30\r\n" );
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document.write( "-------------------------------------------------\r\n" );
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document.write( "x           60/(t+3)     (t+3)/2        30\r\n" );
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document.write( "y           30/t          t             30\r\n" );
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document.write( "difference              (3/2)\r\n" );
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\n" ); document.write( " $\"t-%28t%2B3%29%2F2=3%2F2\"$ \r
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\n" ); document.write( "\n" ); document.write( "Solving that equation gives $\"highlight_green%28t=6%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "Speed for x, $\"30%2F%286%2B3%29=30%2F9=10%2F3=highlight%283%261%2F3%29\"$ $\"k%2Fhour\"$
\n" ); document.write( "Speed for y, $\"highlight%285%29\"$ $\"k%2Fhour\"$ \r
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\n" ); document.write( "\n" ); document.write( "A different opinion or approach may be good. \n" ); document.write( "

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