document.write( "Question 1164920: At noon, Terence and Linda drove from town A to town B. Terrence's avg speed for the whole journey was 15km/h faster than Linda's.when Terrence reached town B at 4 pm, Linda had only covered 224km. What was the distance between town A and town B?? \n" ); document.write( "

Algebra.Com's Answer #789355 by ikleyn(52866) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( " Solution 1\r
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document.write( "Let d be the distance between the cities A and B.\r\n" );
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document.write( "Terence' traveled time was 4 hours (from noon till 4pm).\r\n" );
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document.write( "Hence, Terence' average speed was    hours.\r\n" );
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document.write( "It means that the Linda's average speed was   km/h  (15 km/h slower than that of Terence).\r\n" );
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document.write( "In 4 hours, from noon till 4 pm, Linda covered 224 kilometers.\r\n" );
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document.write( "It gives you this equation\r\n" );
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document.write( "     = 224,  or\r\n" );
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document.write( "     =  = 56.\r\n" );
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document.write( "Multiply both sides by 4 to get\r\n" );
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document.write( "    d - 60 = 56*4 = 224\r\n" );
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document.write( "    d = 224 + 60 = 284.\r\n" );
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document.write( "ANSWER.  The distance between the cities is 284 km.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( " Solution 2\r
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document.write( "Another way to solve this problem is to write so called  \"speed equation\"\r\n" );
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document.write( "     -  = 15\r\n" );
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document.write( "Saying that the difference between two speeds,    and   is 15 km/h.\r\n" );
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document.write( "Then from the equation you get\r\n" );
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document.write( "     - 56 = 15,\r\n" );
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document.write( "     = 15 + 56 = 71,\r\n" );
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document.write( "    d = 4*71 = 284,\r\n" );
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document.write( "giving the same answer.\r\n" );
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\n" ); document.write( "\n" ); document.write( " Solution 3\r
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\n" ); document.write( "\n" ); document.write( "In this way, you even may solve the problem MENTALLY, without using equations.\r
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document.write( "The average speed of Linda is   = 56 km/h.\r\n" );
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document.write( "The average speed of Terence is 15 km/h faster, i.e.  56+15 = 71 km/h.\r\n" );
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document.write( "Then the distance from A to B, which Terence covers in 4 hours, is  71*4 = 284 kilometers.\r\n" );
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\n" ); document.write( "\n" ); document.write( "It is the same solution as in Version #2 in this post, simply presented in wording form.\r
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