document.write( "Question 108278: 19 Roofing: A flat roof 28 ft long and 16 ft wide has a 3-in depth of water sitting on it. What is the weight of the water on the roof? \n" ); document.write( "
Algebra.Com's Answer #78930 by bucky(2189)\"\" \"About 
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The volume of water on the roof can be found by multiplying the length of the roof (28 ft) by
\n" ); document.write( "the width of the roof (16 ft) by the depth of the water in feet. The 3 inch depth translates
\n" ); document.write( "to 1/4 ft. This means that the volume (V) of the water is:
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\n" ); document.write( "V = 28 * 16 * (1/4)
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\n" ); document.write( "And since 1/4 times 16 is 4, the volume equation becomes:
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\n" ); document.write( "V = 28 * 4 = 112 cubic feet
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\n" ); document.write( "One cubic ft of water weighs 62.4 lbs (Pocket Reference Third Edition, Thomas J. Glover, Sequoia
\n" ); document.write( "Publishing, Inc., Littleton, CO, Nov 2005, pg 638).
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\n" ); document.write( "Therefore, the total weight of the water on the roof is:
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\n" ); document.write( "112 cu ft * 62.4 lbs/cu ft = 6988.8 lbs
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\n" ); document.write( "That's nearly 3.5 tons of water pushing down on that roof!!!
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\n" ); document.write( "Hope this helps you to understand the problem and how to calculate the answer.
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