document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1164802>Question 1164802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bank loaned out $7,500, part of it at the rate of 14% annual interest, and the rest at 9% annual interest. The total interest earned for both loans was $825.00. How much was loaned at each rate?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #789262 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=789262\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a quick and easy path to the solution, if a solution using formal algebra is not required.<br><BR>\n" );
document.write( "$825 interest on $7500 is an interest rate of 825/7500 = 0.11 = 11%.<br><BR>\n" );
document.write( "11% is 2/5 of the way from 9% to 14%.<br><BR>\n" );
document.write( "Therefore, 2/5 of the money was loaned at the higher rate.<br><BR>\n" );
document.write( "ANSWER: 2/5 of $7500, or $3000, at 14%; the other $4500 at 9%.<br><BR>\n" );
document.write( "CHECK: .14(3000)+.09(4500) = 420+405 = 825<br><BR>\n" );
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