document.write( "Question 1164786: I am trying to graph 3y= -5x, I tried by substituting x for 0 then y for 0. I ended up somehow getting 0,1/3. I just tried again and I was able to get 0,-3. I have looked it up to see if i was right or not because I wasn't sure and it did something completely different. So now im all messed up and I have no idea if what I am trying is the right thing, can you help? \n" ); document.write( "
Algebra.Com's Answer #789239 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "I am trying to graph 3y= -5x, I tried by substituting x for 0 then y for 0. I ended up somehow getting 0,1/3. I just tried again and I was able to get 0,-3. I have looked it up to see if i was right or not because I wasn't sure and it did something completely different. So now im all messed up and I have no idea if what I am trying is the right thing, can you help?
\n" ); document.write( "
You don't need to substitute 0 for x and 0 for y, since when you solve the equation for y, b, or the y-intercept is 0, and if the y-intercept is 0, the x-intercept will also be 0 ====> \"matrix%282%2C3%2C+3y%2C+%22=%22%2C+-+5x%2C+y%2C+%22=%22%2C+%28-+5%2F3%29x%29\"\r\n" );
document.write( "With a slope of \"-+5%2F3\", we get  .\r\n" );
document.write( "\r\n" );
document.write( "Starting at the y-intercept, (0, 0) and using slope \"%28-+5%29%2F3\" ===> going DOWN 5 units, and RIGHT 3 units will lead to a 2nd point. You can now connect the points to get the graph. \r\n" );
document.write( "\r\n" );
document.write( "Likewise, starting at the y-intercept, (0, 0) and using slope \"%22+%2B+5%22%2F%28-+3%29\" ===> going UP 5 units, and LEFT 3 units will lead to a 2nd point. You can now connect the points to get the graph.\r\n" );
document.write( "That's ALL!!
\n" ); document.write( "
\n" );