document.write( "Question 1164757: Kevin will spend at most $28 on gifts. So far, he has spent $16. Whats re the possible additional amount he will spend? \r
\n" ); document.write( "\n" ); document.write( "Use (c) for the additional amount (in dollars) kevin will spend
\n" ); document.write( "Write your answer as an inequality solved for c.
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Algebra.Com's Answer #789177 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "16 = amount spent so far
\n" ); document.write( "c = additional amount to spend
\n" ); document.write( "16+c = total amount he will spend (previous + additional)\r
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\n" ); document.write( "\n" ); document.write( "We want this total (16+c) to be 28 or smaller. So we want 16+c to be less than or equal to 28.\r
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\n" ); document.write( "\n" ); document.write( "The inequality to solve is \"16%2Bc+%3C=+28\". To isolate c, we undo the addition happening to it. So we'll subtract 16 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"16%2Bc+%3C=+28\"\r
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\n" ); document.write( "\n" ); document.write( "\"16%2Bc-16+%3C=+28-16\"\r
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\n" ); document.write( "\n" ); document.write( "\"c+%3C=+12\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore Kevin the additional amount Kevin can spend is at most $12. He can spend $12 or he can spend less than this amount. \r
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\n" ); document.write( "\n" ); document.write( "Side note: your teacher may want you to restrict that c cannot be negative. So you may need to say \"0+%3C=+c+%3C=+12\". Of course, its best to ask your teacher to clarify.
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