document.write( "Question 1164720: From sale force of 150 persons, one will be selected to attend a special sales meeting. If 52 of them are unmarried, 72 are college graduates, and ¾ of the 52 that are unmarried are college graduates, find the probability that the sales person selected at random will be neither single nor a college graduate. \n" ); document.write( "
Algebra.Com's Answer #789150 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If of the 52 unmarried are college graduates, then 39 are both unmarried and college graduates. Then 52 minus 39 = 13 are unmarried and not college graduates and 72 minus 39 = 33 are college graduates that are not unmarried. So 13 + 39 + 33 are either unmarried, college graduates, or both. The rest of the 150, you do the arithmetic, are both not unmarried and not college graduates.\r
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\n" ); document.write( "\n" ); document.write( "However, you cannot answer this question with the information given. Just because a person is unmarried doesn't mean they are single. So know the number of unmarried out of a particular group allows you to figure the number that are married, but you cannot figure the number that are not single. If your instructor made up this question or gave it to you after s/he read it, then you are not being taught by a mathematician. If you are paying tuition, I would ask for a refund.\r
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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