document.write( "Question 108296: At 10:00 A.M. a car leaves a house at a rate of 60mi/h. At the same time another car leaves the same house at a rate of 50mi/h in the opposite direction. At what time will the cars be 330 miles apart? \n" ); document.write( "
Algebra.Com's Answer #78909 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! At 10:00 A.M. a car leaves a house at a rate of 60mi/h. At the same time another car leaves the same house at a rate of 50mi/h in the opposite direction. At what time will the cars be 330 miles apart? \n" ); document.write( "----------- \n" ); document.write( "1st car DATA: \n" ); document.write( "rate = 60 mph ; time = x hrs ; distance = rt = 60x miles \n" ); document.write( "---------------------- \n" ); document.write( "2nd car DATA: \n" ); document.write( "rate = 50 mph ; time = x hrs ; distance = rt = 50x miles \n" ); document.write( "----------- \n" ); document.write( "EQUATION: \n" ); document.write( "distance + distance = 330 miles \n" ); document.write( "60x + 50x = 330 \n" ); document.write( "110x = 330 \n" ); document.write( "x = 3 hrs \n" ); document.write( "-------- \n" ); document.write( "10:00 AM + 3 hrs = 1:PM \n" ); document.write( "========= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |