document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1978>Question 1978</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If p=3^(20-q) using logarithms express q in terms of p </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #789 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=789\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> take logs to base 3,\r<BR>\n" );
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document.write( "logp = 20-q<BR>\n" );
document.write( "so q = 20 - logp\r<BR>\n" );
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document.write( "where log is log_base3: if p=9, then logp would be 2, then q=18.\r<BR>\n" );
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document.write( "in the original...3^(20-18) is 3^2 --> 9\r<BR>\n" );
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document.write( "so 2 equations are equivalent\r<BR>\n" );
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document.write( "jon. </SPAN>\n" );
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