document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1164548>Question 1164548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Holly is x years old. Her brother is 4 years older than holly. Her father is 3 times older than Holly. The sum of all their ages is 104. Wright and solve an equation to find Holly's age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #788952 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=788952\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Holly is x years old. Her brother is 4 years older than holly. Her father is 3 times older than Holly. The sum of all their ages is 104. Wright [sic] and solve an equation to find Holly's age.<BR>\n" );
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document.write( "Holly = x<BR>\n" );
document.write( "Brother = x+4<BR>\n" );
document.write( "Father = x + 3x = 4x<BR>\n" );
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document.write( "Sum = 6x+4 = 104<BR>\n" );
document.write( "x = 50/3 years<BR>\n" );
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document.write( "3 times older is not the same as \"3 times as old\"<BR>\n" );
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document.write( "1 time older = x+x = 2x as old<BR>\n" );
document.write( "2 times older = x+2x = 3x as old<BR>\n" );
document.write( "etc </SPAN>\n" );
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