document.write( "Question 108212: ella and jim are jogging.ella runs from point A to point B in one hour and 2 miles per hour faster than jim does. if jim takes 1/2 hour more than ella to go the same distance,find the distance between points A and B. \n" ); document.write( "
Algebra.Com's Answer #78886 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! ella and jim are jogging. ella runs from point A to point B in one hour and 2 miles per hour faster than jim does. if jim takes 1/2 hour more than ella to go the same distance,find the distance between points A and B. \n" ); document.write( ": \n" ); document.write( "Let x = distance from A to B \n" ); document.write( ": \n" ); document.write( "Given: \n" ); document.write( "E's time = 1 hr \n" ); document.write( "J's time = 1.5 hrs \n" ); document.write( ": \n" ); document.write( "Write a speed equation: Speed = Distance/time: \n" ); document.write( ": \n" ); document.write( "E's speed = J's speed + 2 \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by 3: \n" ); document.write( "3* \n" ); document.write( ": \n" ); document.write( "Cancel out the denominators and you have: \n" ); document.write( "3x = 2x + 6 \n" ); document.write( "3x - 2x = 6 \n" ); document.write( "x = 6 mi from A to B \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the speed of each: \n" ); document.write( "6/1 = 6 mph \n" ); document.write( "6/1.5 = 4 mph, (2 mph slower) \n" ); document.write( " |