document.write( "Question 108212: ella and jim are jogging.ella runs from point A to point B in one hour and 2 miles per hour faster than jim does. if jim takes 1/2 hour more than ella to go the same distance,find the distance between points A and B. \n" ); document.write( "
Algebra.Com's Answer #78886 by ankor@dixie-net.com(22740)\"\" \"About 
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ella and jim are jogging. ella runs from point A to point B in one hour and 2 miles per hour faster than jim does. if jim takes 1/2 hour more than ella to go the same distance,find the distance between points A and B.
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\n" ); document.write( "Let x = distance from A to B
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\n" ); document.write( "Given:
\n" ); document.write( "E's time = 1 hr
\n" ); document.write( "J's time = 1.5 hrs
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\n" ); document.write( "Write a speed equation: Speed = Distance/time:
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\n" ); document.write( "E's speed = J's speed + 2
\n" ); document.write( "\"x%2F1\" = \"x%2F1.5\" + 2
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\n" ); document.write( "Multiply equation by 3:
\n" ); document.write( "3*\"x%2F1\" = 3*\"x%2F1.5\" + 3(2)
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\n" ); document.write( "Cancel out the denominators and you have:
\n" ); document.write( "3x = 2x + 6
\n" ); document.write( "3x - 2x = 6
\n" ); document.write( "x = 6 mi from A to B
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\n" ); document.write( "Check solution by finding the speed of each:
\n" ); document.write( "6/1 = 6 mph
\n" ); document.write( "6/1.5 = 4 mph, (2 mph slower)
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