document.write( "Question 1164447: The problem is 8x^3=125. Why can't I simply take the cubed root of both sides to get 2x=5, and from there get x=5/2?\r
\n" ); document.write( "\n" ); document.write( "The solutions I have seen require I move all terms to the left and set the equation equal to zero, factor using difference of cubes formula, and solve from there, giving me x= 5/2, and x=-5+/-5i(square root of 3) all over 4. I don't understand why I can't just solve it as the equation is given, instead of setting everything to 0. Thank you!
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Algebra.Com's Answer #788842 by ikleyn(52817)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "In this concrete case,  you can.\r
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\n" ); document.write( "\n" ); document.write( "In this case,  until you restrict yourself by real numbers,  you can.\r
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\n" ); document.write( "\n" ); document.write( "In more complicated cases,  the cubic root from a number is a  complex number,  and even not one complex number,\r
\n" ); document.write( "\n" ); document.write( "but THREE,  instead.\r
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\n" ); document.write( "\n" ); document.write( "So,  in this complex case,  after taking the cubic root,  you may have  3  values of the cubic root on the left side \r
\n" ); document.write( "\n" ); document.write( "and  3  cubic root values on the right side --- and how then you will decide who is equal to whom ?\r
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\n" ); document.write( "\n" ); document.write( "It is the story . . . \r
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\n" ); document.write( "\n" ); document.write( "After reading the post by tutor @MathTherapy.\r
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document.write( "    When you take the CUBE ROOT, you DO NOT NEED to write +-.\r\n" );
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document.write( "    Until you work with real numbers, keep the sign of the resulting real number (cube root) \r\n" );
document.write( "    SAME as the number UNDER the cube root sign.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The post by @MathTherapy is a mistake.\r
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