document.write( "Question 1164424: Jim began a 206-mile bicycle trip to build up stamina for a triathlete competition. Unfortunately, his bicycle chain broke, so he finished the trip walking. The whole trip took 6 hours. If Jim walks at a rate of 5 miles per hour and rides at 37 miles per hour, find the amount of time he spent on the bicycle. \n" ); document.write( "
Algebra.Com's Answer #788823 by Theo(13342)![]() ![]() You can put this solution on YOUR website! r * t = d \n" ); document.write( "r = rate \n" ); document.write( "t = time \n" ); document.write( "d = distance\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "walking is at 5 miles per hour. \n" ); document.write( "bicycling is at 37 miles per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "total distance is 206. \n" ); document.write( "total time is 6 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "lex x = time walking and let y = time riding the bicycle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y = 6 \n" ); document.write( "5x + 37y = 206\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y is the total time. \n" ); document.write( "5x + 37y is the total distance \n" ); document.write( "in the second equation: \n" ); document.write( "5 is the rate and x is the time. \n" ); document.write( "37 is the rate and y is the time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have two equations that need to be solved simultaneously. \n" ); document.write( "they are: \n" ); document.write( "x + y = 6 \n" ); document.write( "5x + 37y = 206\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of the first equation by 5 and leave the second equation as is to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5x + 5y = 30 \n" ); document.write( "5x + 37y = 206\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract the first equation from the second to get: \n" ); document.write( "32y = 176 \n" ); document.write( "solve for y to get: \n" ); document.write( "y = 5.5 \n" ); document.write( "this makes x = .5 because x + y = 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace x and y with .5 and 5.5 in the original equations to get: \n" ); document.write( "x + y = 6 becomes .5 + 5.5 = 6 which is true. \n" ); document.write( "5x + 37y = 206 becomes 5 * .5 + 37 * 5.5 = 206 which becomes 2.5 + 203.5 = 206 which is also true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = .5 and y = 5.5 is confirmed to be good. \n" ); document.write( "solution is that he rode the bicycle for 5.5 hours.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |