document.write( "Question 1164402: The function f satisfies
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Algebra.Com's Answer #788800 by ikleyn(52805)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "You are given\r\n" );
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document.write( "    \"f%28sqrt%28x%2B1%29%29\" = \"1%2Fx\".    (1)\r\n" );
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document.write( "You want to make the argument of the function f equal to 2.\r\n" );
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document.write( "In other words, you want to have\r\n" );
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document.write( "    \"sqrt%28x%2B1%29\" = 2.\r\n" );
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document.write( "It implies  (after squaring both sides) \r\n" );
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document.write( "    x + 1 = 4,  and then  x = 4-1 = 3.\r\n" );
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document.write( "Indeed,  then  \"sqrt%283%2B1%29\" = \"sqrt%284%29\" = 2.\r\n" );
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document.write( "Very good.   Then at x= 3,  the right side of the equation (1) is  \"1%2Fx\" = \"1%2F3\".\r\n" );
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document.write( "ANSWER.  f(2) = \"1%2F3\".\r\n" );
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