document.write( "Question 1164369: Sandy had some apples and Pears. After selling 1/3 of the apples and 7 pears, the number of pears left was a quarter of the number of apples left. If the number of pears sold was 1/6 the number of the pears that were not sold, how many pears did Sandy have at first?? \n" ); document.write( "
Algebra.Com's Answer #788772 by MathTherapy(10551)\"\" \"About 
You can put this solution on YOUR website!
Sandy had some apples and Pears. After selling 1/3 of the apples and 7 pears, the number of pears left was a quarter of the number of apples left. If the number of pears sold was 1/6 the number of the pears that were not sold, how many pears did Sandy have at first??
\n" ); document.write( "
All the mumbo-jumbo is NOT needed, unless other questions are asked. If this is the only question associated with the problem, then ALL that’s needed is: \r\n" );
document.write( "Sandy had some apples and  pears. After selling 1/3 of the apples and 7 pears, the number of pears left was a quarter of the number of apples left. If the number of pears sold was 1/6 the number of the pears that were not sold, how many pears did Sandy have at first??\r\n" );
document.write( "\r\n" );
document.write( "Let original number of pears Sandy had, be P\r\n" );
document.write( "After selling 7 pears, she had P - 7 pears left\r\n" );
document.write( "With number of pears sold being \"1%2F6\" of unsold pears, we have: \"matrix%281%2C3%2C+7%2C+%22=%22%2C+%281%2F6%29%28P+-+7%29%29\" \r\n" );
document.write( "42 = P  -  7 ------ Multiplying by LCD, 6 \r\n" );
document.write( "42 + 7 = P\r\n" );
document.write( "Original number of pears, or \"highlight_green%28matrix%281%2C3%2C+P%2C+%22=%22%2C+49%29%29\"\r\n" );
document.write( "That's ALL! \r\n" );
document.write( "There's ABSOLUTELY nothing else that you need to do! Doing anything else is totally unnecessary unless you have time to waste!
\n" ); document.write( "
\n" );