document.write( "Question 1164377: Find the consecutive odd integers such that the sum of the least integer and the middle integer is 49 more than the greatest integer.
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Algebra.Com's Answer #788759 by ikleyn(52787)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Let x be the smallest odd number of these three.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then the integers are x, (x+2) and (x+4).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The condition requires\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " x + (x+2) = (x+4) + 49.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify and find x.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 2x + 2 = x + 53\r\n" ); document.write( "\r\n" ); document.write( " 2x - x = 53 - 2\r\n" ); document.write( "\r\n" ); document.write( " x = 51.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. The three numbers are 51, 53 and 55.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |