document.write( "Question 1164359: A coffee merchant combines coffee that costs $7 per pound with coffee that costs $3.30 per pound. How many pounds of each should be used to make 25 lb of a blend costing $5.89 per pound?
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Algebra.Com's Answer #788738 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Another tutor has shown a solution by the standard algebraic method. It is a method you should know and be able to use, as it is applicable to a wide range of similar two-part \"mixture\" problems.

\n" ); document.write( "If speed of finding an answer is important (as in a timed math competition) and formal algebra is not required, here is a quick way to answer any question like this with logical reasoning and some mental arithmetic.

\n" ); document.write( "(The mental arithmetic in this example might be a stretch for many students; but the path to the final answer will still be faster than with formal algebra.)

\n" ); document.write( "Consider the three per-pound prices on a number line: 3.30, 5.89, and 7.00.

\n" ); document.write( "The price of the mixture is 259/370 = 7/10 of the way from 3.30 to 7.00. (3.30 to 7.00 is a difference of 3.70; 3.30 to 5.89 is a difference of 2.59. 2.59/3.70 = 259/370 = 7/10.)

\n" ); document.write( "That means 7/10 of the mixture is the more expensive coffee.

\n" ); document.write( "ANSWER: 7/10 of 25 pounds, or 17.5 pounds, of the more expensive coffee; the other 7.5 pounds of the less expensive.

\n" ); document.write( "CHECK:
\n" ); document.write( "17.5(7.00)+7.5(3.30) = 122.5+24.75 = 147.25
\n" ); document.write( "25(5.89) = 147.25

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