document.write( "Question 108260: Please solve:\r
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document.write( "Two front-end loaders can remove 3/4 of the dirt from an excavation in 1 4/5 days. Working alone, loader A would take 2 days longer than loader B working alone to remove all the dirt. How long for A to do the job completely by itself?\r
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document.write( "Thanks. \n" );
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Algebra.Com's Answer #78872 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 3/4=.75 of all the dirt in 1 4/5 or 1.8 days \n" ); document.write( "the full job of removing all the dirt is: \n" ); document.write( "1.8/.75=2.4 days. \n" ); document.write( "to formula for working together is: \n" ); document.write( "(x+y)/xy \n" ); document.write( "(x+x+2)/x(x+2)=1.8 \n" ); document.write( "(2x+2)/(x^2+2x)=1.8 now cross multiply \n" ); document.write( "1.8x^2+3.6x=2x+2 \n" ); document.write( "1.8x^2+3.6x-2x-2=0 \n" ); document.write( "1.8x^2+1.6x-2=0 \n" ); document.write( "using the quadratic equation we get: \n" ); document.write( " \n" ); document.write( "x=(-1.6+-sqrt[1.6^2-4*1.8*-2])/2*1.8 \n" ); document.write( "x=(-1.6+-sqrt[2.56+14.4])/3.6 \n" ); document.write( "x=(-1.6+-sqrt[16.96])/3.6 \n" ); document.write( "x=(-1.6+-4.12)/3.6 \n" ); document.write( "x=(-1.6+4.12)/3.6 \n" ); document.write( "x=2.52/3.6 \n" ); document.write( "x=.7 days for the B loader. \n" ); document.write( ".7+2=2.7 days for the A loader. \n" ); document.write( "proof \n" ); document.write( "(.7+2.7)/.7*2.7=1.8 \n" ); document.write( "3.4/1.89=1.8 \n" ); document.write( "1.8=1.8 \n" ); document.write( " \n" ); document.write( " |