document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1164342>Question 1164342</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the HCF of 90 126 and 270 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #788703 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13196)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=788703\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "(1) 270 is 3 times 90; so the HCF of 90, 126, and 270 is the HCF of 90 and 126.<br><BR>\n" );
document.write( "(2) As an alternative to the process used by the other tutor to find the HCF of two numbers, I prefer this method:<BR>\n" );
document.write( "(a) make a fraction of the two numbers<BR>\n" );
document.write( "(b) reduce to lowest terms<BR>\n" );
document.write( "The HCF is the number you divided by to do the simplification.<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90%2F126+=+%2818%2A5%29%2F%2818%2A7%29+=+5%2F7 ALIGN=MIDDLE  ALT=\"90%2F126+=+%2818%2A5%29%2F%2818%2A7%29+=+5%2F7\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "The HCF is 18.<br><BR>\n" );
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