document.write( "Question 1164328: 10% of the oil in tank was drawn out and if the tank was originally 2/3 full what fraction of tank is now empty.?. \n" ); document.write( "

Algebra.Com's Answer #788694 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Originally, the tank was    full.\r\n" );
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document.write( "10% of this volume was drawn out.\r\n" );
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document.write( "It means that remaining  OIL volume in the tank  is   -  =  =  =   of the full tank capacity.\r\n" );
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document.write( "Hence, the tank is  now  1 -  =   empty.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "The solution and the answer by @josgarithmetic BOTH ARE WRONG.\r
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