document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=108198>Question 108198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this equation:<BR>\n" );
document.write( "x-3y=0<BR>\n" );
document.write( "2x+3y+3z=18<BR>\n" );
document.write( "x+2y-4z=10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78869 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78869\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> subtracting the first equation from the third gives 5y-4z=10\r<BR>\n" );
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document.write( "subtracting 2 times the first equation from the second gives 9y+3z=18\r<BR>\n" );
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document.write( "(4/3)(9y+3z=18) ... 12y+4z=24 ... adding 5y-4z=10 gives 17y=34 ... y=2\r<BR>\n" );
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document.write( "x-(3)*(2)=0 ... x=6\r<BR>\n" );
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document.write( "6+2(2)-4z=10 ... -4z=0 ... z=0 </SPAN>\n" );
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