document.write( "Question 108197: shawn has an annual interest income of $3290 from two investments. he has $7000 more invested at 8% than he has invested at 6%. find the amount invested in each rate ? \n" ); document.write( "
Algebra.Com's Answer #78862 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! shawn has an annual interest income of $3290 from two investments. he has $7000 more invested at 8% than he has invested at 6%. find the amount invested in each rate ? \n" ); document.write( "======================================= \n" ); document.write( ".08x+.06y=3290 \n" ); document.write( "y=x+7000 \n" ); document.write( "------------------- \n" ); document.write( ".08x+.06(x+7000)=3290 \n" ); document.write( ".08x+.06x+420=3290 \n" ); document.write( ".14x=2870 \n" ); document.write( "x=20500 \n" ); document.write( ".08(20500)+.06y=3290 \n" ); document.write( "1640+.06y=3290 \n" ); document.write( ".06y=1650 \n" ); document.write( "y=27500 \n" ); document.write( "=================== \n" ); document.write( "At 8% interest = $20500 \n" ); document.write( "at 6%interest = $27500 \n" ); document.write( ":) \n" ); document.write( " |