document.write( "Question 108197: shawn has an annual interest income of $3290 from two investments. he has $7000 more invested at 8% than he has invested at 6%. find the amount invested in each rate ? \n" ); document.write( "
Algebra.Com's Answer #78862 by elima(1433)\"\" \"About 
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shawn has an annual interest income of $3290 from two investments. he has $7000 more invested at 8% than he has invested at 6%. find the amount invested in each rate ?
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\n" ); document.write( ".08x+.06y=3290
\n" ); document.write( "y=x+7000
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\n" ); document.write( ".08x+.06(x+7000)=3290
\n" ); document.write( ".08x+.06x+420=3290
\n" ); document.write( ".14x=2870
\n" ); document.write( "x=20500
\n" ); document.write( ".08(20500)+.06y=3290
\n" ); document.write( "1640+.06y=3290
\n" ); document.write( ".06y=1650
\n" ); document.write( "y=27500
\n" ); document.write( "===================
\n" ); document.write( "At 8% interest = $20500
\n" ); document.write( "at 6%interest = $27500
\n" ); document.write( ":)
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