document.write( "Question 1164286: Margaret bought 150 kg of beans of which 20% were red beans, 10% were green beans and the rest were black beans. She changed her order such that the percentage of red beans increased to 30% and the order of black beans was reduced by 20%. What percentage of green beans did she have after she changed the order...?.. \n" ); document.write( "

Algebra.Com's Answer #788599 by Theo(13342) $\"\"$ $\"About$

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total amount of beans was 150 kilograms.
\n" ); document.write( "20% were red.
\n" ); document.write( "10% were green.
\n" ); document.write( "the rest were black.
\n" ); document.write( "that gets you
\n" ); document.write( ".20 * 150 = 30 kilograms of red
\n" ); document.write( ".10 * 150 = 15 kilograms of green
\n" ); document.write( "150 - 145 = 105 kilograms of blackshe
\n" ); document.write( "she changed her order such that the percentage of red beans increased to 30% (not by 30%) and the order of black beans was reduced by 20% (not to 20%).
\n" ); document.write( "based on the above statement, the following occurred:
\n" ); document.write( "the amount of red beans became .30 * `150 = 45 kilograms.
\n" ); document.write( "the amount of black beans became 105 - .20 * 105 = 84 kilograms.
\n" ); document.write( "the amount of green beans became 150 minus 45 minus 84 = 21 kilograms.
\n" ); document.write( "the percent of green beans became 21 / 150 = .14 = 14%.
\n" ); document.write( "your solution is:
\n" ); document.write( "the percentage of green beans became 14% after the change in the order.\r
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