document.write( "Question 1164284: In 2002, a salesman’s monthly income was $1500 for the first 6 months. It was 25% less for the rest of the year. His total income was 20% more than his total income in 2001. Find the average monthly income in 2001.?. \n" ); document.write( "

Algebra.Com's Answer #788596 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " This problem is solved in 5 (five) steps.\r
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document.write( "(1)  His income in the first half of the year 2002 was  1500*6 = 9000  dollars.\r\n" );
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document.write( "(2)  His income in the second half of the year 2002 was  9000*0.75 = 6750  dollars.\r\n" );
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document.write( "(3)  His total income in the year 2002 was  9000 + 6750 = 15750  dollars.\r\n" );
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document.write( "(4)  Let X be his total income in the year 2001.  Then  1.2X = 15750;  hence,  X =  = 13125 dollars.\r\n" );
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document.write( "(5)  Now his average monthly income in the year 2001 was   = 1093.75 dollars.     ANSWER\r\n" );
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