document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1164181>Question 1164181</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the next three terms of the sequence, 49,44,39,34,29 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #788492 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=788492\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> looks like you're subtracting 5 from each preceding term to get the current term starting with the first term being the preceding term.<BR>\n" );
document.write( "49 - 5 = 44 - 5 = 39 - 5 = 35 - 5 = 29<BR>\n" );
document.write( "the sequence formula to use if An = A1 + (n-1) * d<BR>\n" );
document.write( "A1 is 49<BR>\n" );
document.write( "d is -5<BR>\n" );
document.write( "when n = 1, the formula becomes A1 = 49 + 0 * -5 = 49<BR>\n" );
document.write( "when n = 2, the formula becomes A2 = 49 + 1 * -5 = 44<BR>\n" );
document.write( "when n = 3, the formula becomes A3 = 49 + 2 * -5 = 39<BR>\n" );
document.write( "etc.....<BR>\n" );
document.write( " </SPAN>\n" );
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