document.write( "Question 1164162: A lizard jumps stright up from the ground. The lizard lands on a leaf that was directly above where it jumped from. Although the lizard jumped upward with an initial velocity of +8m/s, when he landed on the leaf his final velocity was just -2m/s\r
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Algebra.Com's Answer #788466 by ikleyn(52908)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "To answer question (a), the physicist writes the energy conservation law equation\r\n" );
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document.write( "    mgh = \"%28mv%5B1%5D%5E2%29%2F2\" - \"%28mv%5B2%5D%5E2%29%2F2\"\r\n" );
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document.write( "saying the the potential energy increment mgh is the difference of the initial kinetic energy and the final kinetic energy.\r\n" );
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document.write( "Here m is the mass of the lizard, which we can cancel in both sides of the equation;\r\n" );
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document.write( "g is the gravity acceleration, g = 9.81 m/s^2, or 10 m/s^2 , approximately;\r\n" );
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document.write( "h is the difference of the levels  (= \"how high above the ground\");\r\n" );
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document.write( "\"v%5B1%5D\"  and  \"v%5B2%5D\"  are the given velocities.\r\n" );
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document.write( "So, after canceling the mass \"m\" in both sides and substituting the given data, we get\r\n" );
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document.write( "    10h = \"8%5E2%2F2\" - \"%28-2%29%5E2%2F2\" = \"64%2F2\" - \"4%2F2\" = 32 - 2 = 30\r\n" );
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document.write( "      h                                     = 30/10 = 3.\r\n" );
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document.write( "So, the answer to the first question is \"the leaf is 3 meters above the ground\".\r\n" );
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document.write( "To answer question (b), physicist will use the base equation for a uniformly accelerated/decelerated move\r\n" );
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document.write( "     v = gt,\r\n" );
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document.write( "where v is velocity and t is the time (\"g\" is just introduced above).\r\n" );
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document.write( "The time for flying vertically up from the ground to the upperst possible height (till stop) is  \r\n" );
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document.write( "    t = \"v%2Fg\" = \"8%2F10\" = 0.8 seconds.\r\n" );
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document.write( "The time for falling down from the upperst height to get the speed of 2 m/s is\r\n" );
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document.write( "    t = \"v%2Fg\" = \"2%2F10\" = 0.2 seconds.\r\n" );
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document.write( "The total time flying up and down is, thus,  0.8 + 0.2 = 1 second.\r\n" );
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