document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1164150>Question 1164150</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the distance from point x to the centre of a circle is 10cm. if the radius of the circle 6cm, calculate the length of the tangent from x to the point of contact with the circle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #788439 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=788439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the distance from point x to the centre of a circle is 10cm.<BR>\n" );
document.write( " if the radius of the circle 6cm, calculate the length of the tangent from x to the point of contact with the circle<BR>\n" );
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document.write( "The radius of 6 is from the circle center to the point of contact of the tangent<BR>\n" );
document.write( "A this point it forms a right angle with the tangent<BR>\n" );
document.write( "The hypotenuse = 10 cm, radius is one side, 6 cm<BR>\n" );
document.write( "Let s = dist of x to the point of contact, use the pythag<BR>\n" );
document.write( "s^2 + 6^2 = 10^2<BR>\n" );
document.write( "s^2 = 100 - 36<BR>\n" );
document.write( "s^2 = 64<BR>\n" );
document.write( "s = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2864%29 ALIGN=MIDDLE  ALT=\"sqrt%2864%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "s = 8 cm is the dist from x to the point of contact </SPAN>\n" );
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