document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=108201>Question 108201</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive integers such that when twice the second is subtracted from three times the third, results in 74 ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78842 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> INTEGERS=X,X+1,& X+2.<BR>\n" );
document.write( "3(X+2)-2(X+1)=74<BR>\n" );
document.write( "3X+6-2X-2=74<BR>\n" );
document.write( "X=74-4<BR>\n" );
document.write( "X=70 ANSWER FOR THE FIRST INTEGER.<BR>\n" );
document.write( "70+1=71 NEXT INTEGER.<BR>\n" );
document.write( "70+2=72 LARGEST INTEGER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "3*72-2*71=74<BR>\n" );
document.write( "216-142=74<BR>\n" );
document.write( "74=74 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );