document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1164056>Question 1164056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A merchant  has coffee worth $20 a pound  that she  wishes to mix with 90  pounds of coffee worth $80 a pound to get a mixture that can be sold for $40 a pound . How many  pounds  of the $20 coffee should be used ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #788351 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=788351\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x pounds of $20 coffee and 90 pounds of $80 coffee=20x+$7200 .  units are pounds*dollars/pound=dollars<BR>\n" );
document.write( "20x+7200=(90+x)*$40, the sum of the first two equals the product of the mixture<BR>\n" );
document.write( "20x+7200=3600+40x<BR>\n" );
document.write( "3600=20x<BR>\n" );
document.write( "x=180 pounds of $20 coffee ANSWER\r<BR>\n" );
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document.write( "the mixture will be 270 pounds *$40/pound=$10800<BR>\n" );
document.write( "180*$20=$3600 and $80*90=$7200.  That sum is $10800.<BR>\n" );
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