document.write( "Question 1164019: 3) Fidelity records the number of X-Trails sold each day. This data is used in calculating the following probability distribution of daily sales: \r
\n" ); document.write( "\n" ); document.write( " x P(x)
\n" ); document.write( " 0 0.1
\n" ); document.write( " 1 0.1
\n" ); document.write( " 2 0.2
\n" ); document.write( " 3 0.2
\n" ); document.write( " 4 0.3
\n" ); document.write( " 5 0.1\r
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\n" ); document.write( "\n" ); document.write( "a. Find the probability that the number sold tomorrow will be between 2 and four (inclusive)
\n" ); document.write( "b. Find the probability that the number sold tomorrow will be between 2 (inclusive) and four.
\n" ); document.write( "Please help me solve this question
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Algebra.Com's Answer #788309 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "The answer to part A is 0.5
\n" ); document.write( "The answer to part B is 0.4\r
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\n" ); document.write( "\n" ); document.write( "To get these answers, we add up the P(x) values. However, we only add up specific ones based on the restrictions mentioned.\r
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\n" ); document.write( "\n" ); document.write( "Part A says \"between 2 and four (inclusive)\", which I interpret to mean \"2+%3C+x+%3C=+4\". So x can't equal 2, but it can equal 4. This is the same as saying \"3+%3C=+x+%3C=+4\" only when x is an integer. We'll be adding the P(x) values when x = 3 and x = 4, so we get 0.2+0.3 = 0.5\r
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\n" ); document.write( "\n" ); document.write( "Part B says \"between 2 (inclusive) and four\", so we have \"2+%3C=+x+%3C+4\" now which is the same as \"2+%3C=+x+%3C=+3\" only when x is an integer. We'll be adding the P(x) values when x = 2 and x = 3 to get 0.2+0.2 = 0.4
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