document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1163997>Question 1163997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An executive invests $21,000, some at 6% and the rest at 5% annual interest. If he receives an annual return of $1,180, how much is invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #788286 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=788286\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If a formal algebraic solution is not required, here is a quick and easy informal way of solving two part \"mixture\" problems like this.<br><BR>\n" );
document.write( "All $21,000 invested at 5% would yield $1050 interest; all at 6% would yield $1260 interest.<br><BR>\n" );
document.write( "The actual interest was $1180.<br><BR>\n" );
document.write( "Picture the three amounts on a number line: 1050, 1180, and 1260.  1180 is 13/21 of the way from 1050 to 1260.  (1050 to 1260 is a difference of 210; 1050 to 1180 is a difference of 120; 130/210 = 13/21.)<br><BR>\n" );
document.write( "That means 13/21 of the total was invested at the higher rate.<br><BR>\n" );
document.write( "ANSWER: 13/21 of $21,000, or $13,000, at 6%; the other $8000 at 5%.<br><BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( ".06(13000)+.05(8000) = 780+400 = 1180<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );