document.write( "Question 108166: can anyone help me?:determine the horizontal asymptote of the graph of
\n" ); document.write( "B(t)=1200/1+34e^-0.125t. i have no idea how to solve this. \n" ); document.write( "

Algebra.Com's Answer #78824 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
You can do it two ways.
\n" ); document.write( "Graphically or by analysis.
\n" ); document.write( "Let's do analysis.
\n" ); document.write( "As t gets large, since there is a -.125 coefficient to multiply t in the exponential, the exponential function drops quickly to zero.
\n" ); document.write( "Then function then looks like
\n" ); document.write( " $\"B%28t%29=1200%2F%281%2B34e%5E%28-0.125t%29%29\"$
\n" ); document.write( " $\"B%28t%29=1200%2F%281%2B0%29\"$
\n" ); document.write( " $\"B%28t%29=1200\"$ for large positive t.
\n" ); document.write( "Example: At t=100, B(t)=1199.848
\n" ); document.write( "I'm not sure of the context of this function, that is if t is always positive, like time.
\n" ); document.write( "If not, we can look at what happens when t becomes large in the negative direction.
\n" ); document.write( "In that case (-.125t) becomes very large, and the exponential function becomes very large.
\n" ); document.write( " $\"B%28t%29=1200%2F%281%2B34e%5E%28-0.125t%29%29\"$
\n" ); document.write( " $\"B%28t%29=1200%2F%28infinity%29\"$
\n" ); document.write( " $\"B%28t%29=0\"$ for large negative t.
\n" ); document.write( "Example: At t=-100, B(t)=.000132
\n" ); document.write( "There is a horizontal asymptote at y=1200.
\n" ); document.write( "And if it makes sense in your problem, there is also one at y=0.
\n" ); document.write( "Graphically it's easier to find the asymptotes,
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